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14x^2+16x=9x
We move all terms to the left:
14x^2+16x-(9x)=0
We add all the numbers together, and all the variables
14x^2+7x=0
a = 14; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·14·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*14}=\frac{-14}{28} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*14}=\frac{0}{28} =0 $
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